Daily Archives: May 9, 2018

CHM201: Physical Chemistry Ii TMA2

CHM201: Physical Chemistry Ii TMA2 Question an Answer Question 1 : Calculate the standard entropy change for the following reaction, 2Ag2O(s)→4Ag(s)+O2(g)2Ag2O(s)→4Ag(s)+O2(g); given So[Ag2O]So[Ag2O] = 121.3 J/K·mol, SoSo[Ag(s)] = 42.6 J/K·mol, and So[O2(g)]So[O2(g)] = 205.1 J/K·mol. A. -126.4 J/K B. +126.4 J/K C. +132.9 J/K D. -205.1 J/K Answer to question

CHM291: Practical Chemistry Iii-inorganic TMA4   Question and Answer

   CHM291: Practical Chemistry Iii-inorganic TMA4   Question 1 : potassium aluminum sulfate dodecahydrate is commonly known as _____ A. hydrated potassium aluminum sulfate B. aluminium C. sulfate D. alum Answer to Question 1 is D. alum Question 2 : hard water has a

GST201: TMA3 Nigerian People and culture Question and Answer

GST201: TMA3 Nigerian People and culture Question 1 : The________ state was located on the North bank of all the Niger at its conference with the River kaduna A. Idoma B. Nupe C. Lokoja D. Igala Answer to question 1 is B. Nupe Question

GST201: TMA1 Nigerian People and culture Question and Answer

GST201: TMA1 Nigerian People and culture Question and Answer Question 1 : The Yoruba ethnic group believed to have come into existence between A. 1000-2000AD B. 1000-2000BC C. 2000-1000BC D. 2500-1000BC Answer to Question 1 is D. 2500-1000BC   Question 2 : Oyo empire became

MTH281: Mathematical Method I TMA3

MTH281: Mathematical Method I TMA3 Question 1 : Evaluate the second partial derivative of the functonf(x,y)=2x3y2+y3f(x,y)=2x3y2+y3 A.∂2f∂x2=12xy2,∂2f∂y2=4×3+6y,∂2f∂x∂y=12x2y∂2f∂x2=12xy2,∂2f∂y2=4×3+6y,∂2f∂x∂y=12x2y B.∂2f∂x2=12x2y2,∂2f∂y2=4x+6y,∂2f∂x∂y=10x2y∂2f∂x2=12x2y2,∂2f∂y2=4x+6y,∂2f∂x∂y=10x2y C.∂2f∂x2=12xy,∂2f∂y2=x3+y,∂2f∂x∂y=2x2y∂2f∂x2=12xy,∂2f∂y2=x3+y,∂2f∂x∂y=2x2y D.∂2f∂x2=5x3y2,∂2f∂y2=6×3+6y,∂2f∂x∂y=2x2y2∂2f∂x2=5x3y2,∂2f∂y2=6×3+6y,∂2f∂x∂y=2x2y2   Question 2 : Compute the third derivative ofsinxInxsin⁡xInxusing Leibnitz theorem A.(2x−2−3x−2)cosx−(3x−3+In2x)sinx B.(x−3−x−2)cosx−(x−2+Inx)cosx C.(2x−3−3x−1)sinx−(3x−2+Inx)cosx D.(3x−3−4x−1)sinx−(3x−2+Inx)sinx   Question 3 : Use

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